Column $-I$ Angle of projection |
Column $-II$ |
$A.$ $\theta \, = \,{45^o}$ | $1.$ $\frac{{{K_h}}}{{{K_i}}} = \frac{1}{4}$ |
$B.$ $\theta \, = \,{60^o}$ | $2.$ $\frac{{g{T^2}}}{R} = 8$ |
$C.$ $\theta \, = \,{30^o}$ | $3.$ $\frac{R}{H} = 4\sqrt 3 $ |
$D.$ $\theta \, = \,{\tan ^{ - 1}}\,4$ | $4.$ $\frac{R}{H} = 4$ |
$K_i :$ initial kinetic energy
$K_h :$ kinetic energy at the highest point
$A-1,\,\,B-2,\,\,C-3,\,\,D-4$
$A-4,\,\,B-3,\,\,C-2,\,\,D-1$
$A-4,\,\,B-1,\,\,C-3,\,\,D-2$
$A-3,\,\,B-2,\,\,C-4,\,\,D-1$
If $R$ and $H$ represent the horizontal range and the maximum height achieved by a projectile then which of the relation exists?
A stone is projected from ground at $t = 0$. At the time of projection horizontal and vertical component of velocity are $10\, m/s$ and $20\, m/s$ respectively. Then time at which tangential and normal acceleration magnitude will be equal $(g = 10\, m/s^2)$ [neglect air friction] ......... $\sec$
A ball of mass $160\, g$ is thrown up at an angle of $60^o$ to the horizontal at a speed of $10\, m\,s^{-1}$ . The angular momentum of the ball at the highest point of the trajectcry with respect to the point from which the ball is thrown is nearly ........ $kg\, m^2/s$ $(g\, = 10\, m\,s^{-2})$
Range of a bullet fired at $45^o$ to horizontal is $980m$. If the bullet is fired at same angle from a car travelling horizontally at $18\, km/hr$ towards target then range will be increased by :-
The equation of a projectile is $y =\sqrt{3} x -\frac{ gx ^2}{2}$ the angle of projection is